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A ball is thrown in the air from a ledge. Its height in feet is represented by f(x) = 16(x2 – 5x – 6), where x is the number of seconds since the ball has been thrown. The height of the ball is 0 feet when it hits the ground.How many seconds does it take the ball to reach the ground?

Respuesta :

we are given

equation in height as

[tex]f(x)=16(x^2-5x-6)[/tex]

Since, the height of the ball is 0 feet when it hits the ground

so, we can set f(x)=0

and then we can solve for x

[tex]f(x)=16(x^2-5x-6)=0[/tex]

[tex]16(x^2-5x-6)=0[/tex]

now, we can factor it and then we can solve for x

[tex]16(x-6)(x+1)=0[/tex]

[tex](x-6)=0[/tex]

[tex]x=6[/tex]

So, it takes 6 seconds the ball to reach the ground...........Answer

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