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A man invest 5,200,part at 4% and the balance at 3%. If his total income for the two investments is $194,how much money did he invest at each rate

Respuesta :

Let the amount invested at 4% be = x

Let the amount invested at 3% be = y

Given is:

[tex]x+y=5200[/tex] or [tex]x=5200-y[/tex]  .... (1)

As, total income for the two investments is $194, so equation is:

[tex]0.04x+0.03y=194[/tex]   ....(2)

Putting value of x from (1) in (2)

[tex]0.04(5200-y)+0.03y=194[/tex]

[tex]208-0.04y+0.03y=194[/tex]

[tex]0.01y=14[/tex]

[tex]y=1400[/tex]

And x=5200-y

[tex]x=5200-1400=3800[/tex]

Hence, money invested at 4% is $3800 and money invested at 3% is $1400

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