Answer
cos c = 40/41
Step by step explanation
It is a right triangle.
AB^2 + BC^2 = AC^2
9^2 + 40^2 = 41^2
81 + 1600 = 1681
1681 = 1681
Cos C = Opposite/Hypotenuse
Cos C = 40/41 [opposite = 40 and Hypotenuse = 41]
Thank you.
Answer:
[tex]cos c = \frac{40}{41}[/tex]
Step-by-step explanation:
We have a (right-angled) triangle ABC with the following side lengths:
AB=9,
BC=40; and
CA=41.
We are to find the value of cos c. We know that [tex]cos[/tex]∅[tex]= \frac{base}{hypotenuse}[/tex].
In this case, since we have to find the angle c so the AB will be the opposite, BC the base and AC will be the hypotenuse.
[tex]cos c = \frac{BC}{AC}[/tex]
Therefore, [tex]cos c = \frac{40}{41}[/tex]
