Answer : The correct option is, (B) 6 mole
Explanation :
Given moles of [tex]FeCl_2[/tex] = 6 moles
Given moles of [tex]NaOH[/tex] = 6 moles
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
[tex]FeCl_2+2NaOH\rightarrow Fe(OH)_2+2NaCl[/tex]
From the given balanced reaction, we conclude that
As, 1 moles of [tex]FeCl_2[/tex] react with 2 moles of [tex]NaOH[/tex]
So, 6 moles of [tex]FeCl_2[/tex] react with [tex]\frac{2}{1}\times 6=12[/tex] moles of [tex]NaOH[/tex]
From this we conclude that, [tex]FeCl_2[/tex] is an excess reagent and [tex]NaOH[/tex] is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.
Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH
The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles
Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles
