From the definition of piecewise function we find that
f(x) has been given values for x =-1 and x=1
Thus f is defined for both x =-1 and x=1
When x =-1, we have f(x) = [tex](-1+3)^2-1 = 4-1 = 3[/tex]
When x = 1, we have f(x) = -x
Hence f(1) = -1
Comparing f(-1) = 3 and f(1) =-1 we find that
f(-1)>f(1)
Hene option 1 is right.
Option 2 is wrong since f(-1) is not < f(1)
Option 3 is wrong since f(-1) and f(1) are not equal
Option 4 is wrong since f is defined for both x =-1 and 1.
FInal answer is option 1
