Respuesta :

kenmyna

 The molarity   of potassium  ions  in a 0.122 M  K2CrO4  is 0.244 M


Explanation

write dissociation reaction  for K2CrO4

that  K2CrO4 (aq)→ 2K^+ (aq)  + CrO4^2- (aq)


K2CrO4  dissociate to give  2  ions of potassium ,therefore  the molarity  of potassium ion = 2 x 0.122  = 0.244 M


dsdrajlin

The molarity of potassium ions in a 0.122 M K₂CrO₄ solution is 0.244 M.

K₂CrO₄ is a strong electrolyte that dissociates according to the following equation:

K₂CrO₄(aq) ⇒ 2 K⁺ + CrO₄²⁻(aq)

The molar ratio of K₂CrO₄ to K⁺ is 1:2. The molarity of potassium ions in a 0.122 M K₂CrO₄ solution is:

[tex]\frac{0.122molK_2CrO_4}{L} \times \frac{2molK^{+} }{1molK_2CrO_4} = \frac{0.244molK^{+} }{L}[/tex]

The molarity of potassium ions in a 0.122 M K₂CrO₄ solution is 0.244 M.

You can learn more about molarity here: https://brainly.com/question/16727614