Which graph shows the transformation of the function f(x) = e^x where the function is translated three units to the right, vertically compressed by a factor of 1/4, and then translated six units down.





Original function is f(x) = [tex]e^x[/tex]
For this y intercept = 1. i.e. passes through (0,1)
First it is translated three units to the right.
So y = [tex]e^(x-3)[/tex]
When vertically compressed by a factor of 1/4 we have
y = [tex]4e^(x-3)[/tex]
Next is translated 6 units down
i.e. new graph would be
y = [tex]4e^(x-3)[/tex]+6
When x =3, y =6.
When y =-6, x tends to infinity.
i.e. y =-6 is an asymptote
Hence we find that 4th graph is the correct answer.
Answer:
C is correct graph.
Step-by-step explanation:
Given: [tex]f(x)=e^x[/tex]
Now we do some operation on function f(x)
Step 1: f(x) is translated 3 units to the right.
For a unit right translation, x changes to
[tex]x\rightarrow x-a[/tex]
Therefore, [tex]f(x)=e^{x-3}[/tex]
Step 2: Vertical compressed by a factor of [tex]\frac{1}{4}[/tex]
For vertical compressed. f(x) changes to a f(x)
[tex]f(x)=\frac{1}{4}e^{x-3}[/tex]
Step 3: Translated 6 unit down
For this translation, y changes to
[tex]y\rightarrow y-6[/tex]
Therefore, [tex]f(x)=\frac{1}{4}e^{x-3}-6[/tex]
Final function after three steps we get,
[tex]f(x)=\frac{1}{4}e^{x-3}-6[/tex]
Please see the attachment for correct graph.
Thus, C is correct graph.