Respuesta :
[tex](x^2−x−12)/(2x^2)÷(x^2+x−6)/2x^3[/tex]
First write the given term in the correct form by multiplying with reciprocal of denominator.
Given term = [tex](x^2−x−12)*2x^3/(2x^2)*(x^2+x-6)[/tex]
Now we find that numerator = [tex](x^2−x−12)*2x^3[/tex]
= [tex]2x^3(x-4)(x+3)[tex]
Similarly denominator = [tex]2x^3/(2x^2)*(x^2+x-6)[tex]
=[tex](2x^3(x+3)(x-2)[tex]
Common factor in both numerator and denominator = [tex][2x^2(x+3)(xtex]
So cancel this to get
[tex]x(x-4)/(x-2)[tex]
