Answer-
From 61.21 km on a clear day you could see from the top of the Eiffel Tower.
Solution-
From the attachment,
OA = Distance between the top of the Eiffel Tower and center of the earth = 6240 km + 300 m = 6240 km + 0.300 km = 6240.3 km
OB = Radius of the earth = 6240 km
Applying trigonometric properties,
[tex]\Rightarrow\cos \theta=\dfrac{OB}{OA}\\\\\Rightarrow \theta=\cos^{-1}\dfrac{OB}{OA}\\\\\Rightarrow \theta=\cos^{-1}\dfrac{6240}{6240.3}\\\\\Rightarrow \theta=0.562[/tex]
So,
[tex]\text{Circumference of the earth} = 2\pi \times radius = 2\pi \times 6240=12480\pi=39207 km[/tex]
So, the arc length will be,
[tex]=\dfrac{0.562}{360}\times 39207\\\\=61.21\ km[/tex]
Therefore, from 61.21 km on a clear day you could see from the top of the Eiffel Tower.
