Which is the equation in point-slope form of the line that contains points A and E?

Answer:
y+2 = 3/4(x+4)
or with the other point
y-4 = 3/4 (x-4)
Step-by-step explanation:
We can find the slope of the line since we have 2 points
A(-4,-2) and E(4,4)
m = (y2-y1)/(x2-x1)
= (4--2)/(4--4)
= (4+2)/(4+4)
=6/8
= 3/4
Then we can use point slope form
y-y1 = m(x-x1)
y--2 = 3/4 (x--4)
y+2 = 3/4(x+4)
or with the other point
y-4 = 3/4 (x-4)
Answer:
Point-slope form: [tex]y-4=\dfrac{3}{4}(x-4)[/tex]
Step-by-step explanation:
We are given some points on coordinate plane.
We need to find the equation of line in point slope form which passes through A and E
First we write the coordinate of point A and Point E
Point A: (-4,-2)
Point E: (4,4)
Formula:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-4=\dfrac{-2-4}{-4-4}(x-4)[/tex]
[tex]y-4=\dfrac{3}{4}(x-4)[/tex]
where,
[tex]slope=\dfrac{3}{4}[/tex]
Hence, The slope point form of line is [tex]y-4=\dfrac{3}{4}(x-4)[/tex]