YOU also better mark me BRAINLIEST if someone else answers!!!
1)
volume = 100 mL
density = 1.02 g / mL
mass = density x volume
- Cp = 4.03 J / oc g
- dT = 28.7 - 23.5 = 5.2 oC
- Q = m Cp dT
- Q = 102 x 4.03 x 5.2
- Q = 2138 J
- Q = 2.14 kJ
heat absorbed = 2.14 kJ
2)
- We can calculate the moles of HC1 present in 50 ml 1m solution by using the formula, moles = volume of solution in L*molarity
- moles = 50/1000 = .05 , L*1 M = .05 Moles of HCL.
- The same can be applied for calculation of moles fo Na OH of 50 ml, 1 M solution. (50 ml NaOH = .o5 L NaOH)
- Then use the formula = volume of solution / 1000*moles.wt,
- =1.825 gram.
- moles=mass in grams /moles.wt= .05 moles of HCI
- calculate moles of water from this reaction.
- HC1+NaOH----->NACl+h20 (Balanced Equation)
- .5+.5----> .5+.5
- .05 moles of water
- Delta H=q/n.
- n=.05 to calculate the Delat H.
3) I don't understand it, sorry
