Answer: 51.2 N
Explanation:
The magnitude of the normal force acting on the bag counterbalances the component of the weight which is perpendicular to the incline, equal to:
[tex]W_p = mg cos \theta[/tex]
where
m = 5.4 kg is the mass of the bag
g = 9.81 m/s^2 is the gravitational acceleration
[tex]\theta=15^{\circ}[/tex] is the angle of the incline
Substituting the numbers into the formula, we get
[tex]W_p = (5.4 kg)(9.81 m/s^2 )(cos 15^{\circ}=51.2 N[/tex]
And so, the normal force is also equal to 51.2 N.
