[tex]Solution, \frac{-4r}{4}+\frac{5r}{3}=\frac{2r}{3}[/tex]
[tex]Steps:[/tex]
[tex]\frac{-4r}{4}+\frac{5r}{3}[/tex]
[tex]\frac{-4r}{4},\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b},\\-\frac{4r}{4},\\\mathrm{Divide\:the\:numbers:}\:\frac{4}{4}=1,\\-r,\\-r+\frac{5r}{3}[/tex]
[tex]\mathrm{Convert\:element\:to\:fraction}:\quad \:r=\frac{r3}{3},\\\frac{5r}{3}-\frac{r\cdot \:3}{3}[/tex]
[tex]\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c},\\\frac{5r-r\cdot \:3}{3}[/tex]
[tex]5r-r\cdot \:3,\\\mathrm{Add\:similar\:elements:}\:5r-3r=2r,\\\frac{2r}{3}[/tex]
[tex]The\:Correct\:Answer\:Is\:\frac{2r}{3}[/tex]
[tex]Hope\:This\:Helps!!![/tex]
[tex]-Austint1414[/tex]
