A miner finds a piece of shiny metal while panning for gold. He finds that the metal has a volume of 1.3ml and a mass of 25.1g. What is the density of the metal? (1 decimal place) What did he find?

Respuesta :

Answer: 19.3 g/mL, or 19,300 kg/m^3

Explanation:

The density of the piece of metal is given by:

[tex]d=\frac{m}{V}[/tex]

where

m = 25.1 g is the mass of the piece of metal

V = 1.3 mL is the volume

Substituting the numbers into the formula, we find

[tex]d=\frac{m}{V}=\frac{25.1 g}{1.3 mL}=19.3 g/mL[/tex]

If we want to convert into SI units:

[tex]d=19.3 g/mL = 19.3 g/cm^3 \cdot \frac{0.001 kg/g}{1\cdot 10^{-6} m^3/cm^3}=19300 kg/m^3[/tex]