Respuesta :
Answer
A) the quantity of x squared plus 2x minus 1, all over 7 times the quantity of x plus 5
Step by step explanation
Let's transform verbal expression to algebraic expression.
"the quantity of x plus 4, all over the quantity of 7 − the quantity of x plus 3, all over the quantity of x plus 5"
= (x + 4)/7 - (x + 3)/(x +5)
Here least common multiple is 7 (x + 5)
= [tex]\frac{(x+4)(x +5) - 7(x + 3)}{7(x + 5)}[/tex]
= [tex]\frac{x^2 + 4x + 5x + 20 -7x - 21}{7(x+5)}[/tex]
= [tex]\frac{x^2 + 9x -7x -1}{7(x + 5)}[/tex]
= [tex]\frac{x^2 + 2x - 1}{7(x + 5)}[/tex]
It is "quantity of x squared plus 2x minus 1, all over 7 times the quantity of x plus 5"
Thank you.
Answer:
A is correct.
The quantity of x squared plus 2x minus 1, all over 7 times the quantity and plus 5.
Explanation:
quantity of x plus 4, all over the quantity of 7 − the quantity of x plus 3, all over the quantity of x plus 5
First we write this into rational expression
[tex]\frac{x+4}{7}-\frac{x+3}{x+5}[/tex]
Now we find the LCD of 7 and x+5, i.e 7(x+5)
[tex]\frac{(x+4)(x+5)-7(x+3)}{7(x+5)}[/tex]
[tex]\frac{x^2+9x+20-7x-21}{7x+35)}[/tex]
[tex]\frac{x^2+2x-1}{7x+35)}[/tex]
Now we write the simplified expression into sentence form.
The quantity of x squared plus 2x minus 1, all over 7 times the quantity and plus 5.
