Answer: (b)0.000012/k
Explanation:
The linear expansion of the metal rod is given by
[tex]\Delta L= L_0 \alpha \Delta T[/tex]
where
[tex]\Delta L=0.090 cm[/tex] is the linear expansion
[tex]L_0 = 80 cm[/tex] is the initial length of the rod
[tex]\alpha[/tex] is the linear expansivity
[tex]\Delta T=93.6^{\circ}C=93.6 K[/tex] is the increase in temperature
By re-arranging the equation, we find the linear expansivity:
[tex]\alpha = \frac{\Delta L}{L_0 \Delta T}=\frac{0.090 cm}{(80 cm)(93.6K)}=0.000012 K^{-1}[/tex]