Mrs. Tramel’s most liked Mybook post this summer had 216 reacts and 39 comments. She has 703 FB friends and her husband (who was tagged in the post) has 784 friends. They have 192 mutual friends. What percent of their friends reacted to the post? What percent commented?

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frika frika · Answer 1 · 2018-11-14T21:34:49+01:00

Mrs. Tramel and her husband have

703+784=1487 fruiends, but among them 192 are mutual (counted twice). Then the number of different friends is

1487-192=1295.

Mrs. Tramel’s most liked Mybook post this summer had 216 reacts, then

1295 -- 100%

216 -- x%.

Mathematically,

[tex]\dfrac{1295}{216}=\dfrac{100}{x},\\ \\x=\dfrac{216\cdot 100}{1295}=\dfrac{21600}{1295}=\dfrac{4320}{259}\approx 17\%.[/tex]

Mrs. Tramel’s most liked Mybook post this summer was commented 39 times, then

1295 -- 100%

39 -- y%.

Thus,

[tex]\dfrac{1295}{39}=\dfrac{100}{y},\\ \\y=\dfrac{39\cdot 100}{1295}=\dfrac{3900}{1295}=\dfrac{780}{259}\approx 3\%.[/tex]

alinakincsem alinakincsem · Answer 2 · 2018-11-14T22:45:38+01:00

Answer:

Reacted --> 16.7%

Commented --> 3.01%

Step-by-step explanation:

We know,

the number of Mrs. Tramel have = 703,

the number of friends Mr. Tramel have = 784,

the number of mutail friends Mr. and Mrs. Tramel have = 192

so the total number of friends both Mr. and Mrs. Tramel have (including the mutual friends) = (703+784) - 192 = 1295

Number of reacts on the post = 216

so percentage of friends who reacted on the post = [tex]\frac{216}{1295} × 100[/tex] = 16.7%

and

number of comments on the post = 39

so percentage of friends who commented on the post = [tex]\frac{39}{1295} × 100[/tex] = 3.01%