If F(x)= x2+2x-3 and g(x)=x2-9 , find (f/g)(4) and(f+g)(4) .(f/g)(4) is , and (f+g)(4) is .

f(x) = x^2 + 2x - 3 and g(x) = x^2 - 9
(f/g)(x) = (x^2+ 2x -3) / (x^2 - 9)
(f/g)(x) = (x +3 )(x - 1) / (x + 3)(x - 3)
(f/g)(x) = (x - 1) / (x - 3)
So
(f/g)(4) = (4 - 1)/(4 -3)
(f/g)(4) =3/1
(f/g)(4) = 3
(f+g)(x) = x^2+ 2x - 3 + x^2 - 9
(f+g)(x) = 2x^2 + 2x - 12
(f+g)(x) = 2(4)^2 + 2(4) - 12
(f+g)(4) = 32 + 8 - 12
(f+g)(4) = 28
Answer:
(f/g) (4) (f/g) (4) is 3, and (f + g) (4) (f + g) (4) is 28
Step-by-step explanation:
The first person that answered did the math correctly but made a typo in the answer.