Answer: 20,734.69 N/m
Explanation:
The elastic potential energy (ELPE) of the rubber band is given by
[tex]E=\frac{1}{2}kx^2[/tex]
where
k is the spring constant
x = 0.035 m is the stretching of the rubber band
E = 12.7 J is the ELPE of the rubber band
Substituting the numbers and re-arranging the equation, we find
[tex]k=\frac{2E}{x^2}=\frac{2\cdot 12.7 J}{(0.035 m)^2}=20,734.69 N/m[/tex]
