Y=4•2^x
y = 4 * 2^ -6
y = 2^2 * 2^-6
when the bases are the same add the exponents
y = 2^ (2-6)
y = 2^ -4
negative exponents take it to the denominator if in the numerator
y = 1/ 2^4
y = 1/16
Answer: The value of y is [tex]\dfrac{1}{16}[/tex]
Step-by-step explanation:
Since we have given that
[tex]y=4.2^x[/tex]
We need to find the value of y for x = -6.
So, by putting the value of x in the above equation , we get that
[tex]y=4.2^{-6}\\\\y=\dfraac{4}{2^6}\\\\y=\dfrac{4}{64}\\\\y=\dfrac{1}{16}[/tex]
Hence, the value of y is [tex]\dfrac{1}{16}[/tex]
