Let t hours be the number of hours needed for the second train to catch up the first one.
Then the first train is on the way (t+1) hours.
1. First train travels at a speed of 60 mph (t+1) hours and passes
[tex]60\cdot (t+1)\ m.[/tex]
2. Second train travels at a speed of 70 mph t hours and passes
[tex]70\cdot t\ m.[/tex]
Since two trains will meet, then
[tex]60\cdot (t+1)=70\cdot t,\\ \\60t+60=70t,\\ \\10t=60,\\ \\t=6\ hours.[/tex]
Then they will meet at 7:00 p.m.
Answer: 7:00 p.m.