Respuesta :
pOH is defined as -log([OH-]).
pOH = -log([OH-]) = -log(7.9 * 10^-4) = 3.1
Hope this helps!
Answer: pOH of the given hydroxide ion concentration is 3.10
Explanation:
pOH is defined as the negative logarithm of hydroxide ion concentration. It is represented by the equation:
[tex]pOH=-\log[OH^-][/tex]
We are given:
Hydroxide ion concentration, [tex][OH^-]=7.9\times 10^{-4}M[/tex]
Putting values in above equation, we get:
[tex]pOH=-\log(7.9\times 10^{-4})\\\\pOH=3.10[/tex]
Hence, pOH of the given hydroxide ion concentration is 3.10
