ANSWER
The required line is BC
EXPLANATION
We want to find the line that passes through
[tex](0,1)[/tex]
and has slope
[tex]m = - \frac{4}{5} [/tex]
Since the x-value of the given point is zero, the point
[tex](0,1)[/tex]
is the y-intercept.
From the above graph, the two lines that contains
[tex](0,1)[/tex]
are line CE and line BC.
Since, the slope
[tex]m = - \frac{4}{5} [/tex]
is negative, line BC is the required line because it is sloping backwards.
We can confirm this by using the point,
[tex]B(-5,5)[/tex]
and
[tex]C(0,1)[/tex]
to find the slope and obtain
[tex]m = \frac{5 - 1}{ - 5 - 0} = - \frac{4}{5} [/tex]
