Answer: D) [tex]\dfrac{51}{65}[/tex]
Step-by-step explanation:
The given table is :
Freshman Sophomore Junior Senior
Left-handed batters 4 6 5 4
Right-handed batters 13 10 11 12
From the table, the number of player that are junior =[tex]5+11=16[/tex]
The probability of choosing a junior=[tex]P(J)=\dfrac{16}{65}[/tex]
The number of players that are right- handed = [tex]13+10+11+12=46[/tex]
The probability of choosing right handed batter=[tex]P(R)=\dfrac{46}{65}[/tex]
The probability of choosing a junior and a right handed batter
[tex]P(J\cap R)=\dfrac{11}{65}[/tex]
Now, the number of player that are junior or a right-handed batter is given by :-
[tex]P(J\cap R)=P(J)+P(R)-P(J\cap R)\\\\\Rightarrow P(J\cap R)=\dfrac{16}{65}+\dfrac{46}{65}-\dfrac{11}{65}\\\\\Rightarrow P(J\cap R)=\dfrac{51}{65}[/tex]
