Given:
Mass of ice, m = 160 g
Initial temperature of ice T1 = 0 c
Final temperature, T2 = 77 C
To determine:
The heat required to melt ice
Explanation:
The heat (Q) required is given as:
Q = Heat of fusion of ice + Heat required to raise the temperature of water
Q = mΔHfusion + mcΔT
Now, ΔH(fusion of ice) = 333.55 J/g
specific heat of water, c = 4.18 J/gC
Q = 160 g * 333.55 J.g-1 + 160 g * 4.18 J/gC *(77-0) C
Q = 53368 J + 51498 J = 104866 J
Ans: Heat required = 104.87 kJ
