Given:
Mass of ethanol m = 88 g
Initial temperature T1 = 298 K = (298-273)C = 25 C
Final temperature, T2 = 405 K = (405-273) = 132 C
heat capacity of ethanol, c = 2.42 J/g C
To determine:
The heat required to raise the temperature of ethanol
Explanation:
the heat (Q) required is given as:
Q = mcΔT = mc(T2-T1)
Q = 88.0 g * 2.42 J/gC *(132-25) C = 22786 J
Ans: Heat required = 22.79 kJ