One hundred people were asked, "do you favor stronger laws on gun control?" of the 33 that answered "yes" to the question, 14 were male. of the 67 that answered "no" to the question, six were male. if one person is selected at random, what is the probability that this person answered "yes" or was a male? round the the nearest hundredth.

Respuesta :

The information we have allow us to sketch the following scenario. There are:

  • 14 males who voted yes
  • 19 females who voted yes
  • 6 males who voted no
  • 61 females who voted no

So, the statement "answer yes or be a male" covers the first three bullet points: the only part not covered by the statement is the last bullet point, because it is about females who voted no, so both conditions of the "or" statement are false.

So, out of a total of

[tex] 14+19+6+61=100 [/tex]

people, those who answered yes or are male are

[tex] 14+19+6 = 39 [/tex]

This means that if you pick a person at random, you have a

[tex] \dfrac{39}{100}=0.39 [/tex]

chance of picking someone who meets your criteria.

Probabilities are used to determine the chances of an event.

The probability that a selected person answered "yes" or is "male" is 0.39

The given parameters are:

[tex]n = 100[/tex] -- sample size

[tex]Male\ and\ Yes = 14[/tex]

[tex]Yes = 33[/tex]

[tex]Male\ and\ No = 6[/tex]

[tex]No = 67[/tex]

First, we calculate the number of male respondents

[tex]Male = 14 + 6[/tex]

[tex]Male = 20[/tex]

So, the probability that a selected person answered "yes" or is "male" is:

[tex]Pr = P(Male) + P(Yes) - P(Male\ and\ Yes)[/tex]

This gives

[tex]Pr = \frac{20}{100} + \frac{33}{100} - \frac{14}{100}[/tex]

Express as decimals

[tex]Pr = 0.20 + 0.33 - 0.14[/tex]

[tex]Pr = 0.39[/tex]

Hence, the required probability is 0.39

Read more about probabilities at:

https://brainly.com/question/11234923