Answer:
3.46 s
Explanation:
First of all, we can calculate the acceleration of the elevator by using Newton's second law:
[tex]F=ma\\a=\frac{F}{m}=\frac{3000 N}{1200 kg}=2.5 m/s^2[/tex]
and the acceleration has the same direction of the net force (upward).
Now we can calculate the time takes for the elevator to cover a distance of S=15 m by using the following SUVAT equation:
[tex]S=\frac{1}{2}at^2[/tex]
where a is the acceleration and t the time. Re-arranging the equation, we find
[tex]t=\sqrt{\frac{2S}{a}}=\sqrt{\frac{2(15 m)}{2.5 m/s^2}}=3.46 s[/tex]
Time taken to travel up the 15m is 3.46s.
When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
The acceleration of the elevator by using Newton's second law
a = F/m
a = 3000/1200 = 2.5 m/s²
and the acceleration has the same direction of the net force (upward).
Time taken for the elevator to cover a distance of S=15 m
s = ut +1/2 at² where u =initial velocity = 0 m/s
Substitute the value, we get the time
t = sq rt (2s/a)
t = sq rt (2 x 15/2.5)
t =3.46 s.
Thus, the time taken to travel 15 m is 3.46s.
Learn more about net force.
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