Respuesta :
Answer:
(1)
option-b
(2)
option-d
(3)
option-a
(4)
option-d
(5)
option-d
Step-by-step explanation:
(1)
previous value =$40
new value =$44
so, change = new value - previous value
change =44-40
change =4
percent of change = ((change)/(previous value))*100
percent of change is
[tex]=\frac{4}{40}\times 100[/tex]
percent of change is 10%..................Answer
(2)
previous value =$450
new value =$396
so, change = new value - previous value
change =396-450
change =-54
percent of change = ((change)/(previous value))*100
percent of change is
[tex]=\frac{-54}{450}\times 100[/tex]
[tex]=-12[/tex]
percent of change is -12%..................Answer
(3)
previous value =20
new value =24
so, change = new value - previous value
change =24-20
change =4
percent of change = ((change)/(previous value))*100
percent of change is
[tex]=\frac{4}{20}\times 100[/tex]
[tex]=20[/tex]
percent of change is 20%..................Answer
(4)
previous value =150 pounds
new value =138 pounds
so, change = new value - previous value
change =138-150
change =-12
percent of change = ((change)/(previous value))*100
percent of change is
[tex]=\frac{-12}{150}\times 100[/tex]
[tex]=-8[/tex]
percent of change is -8%..................Answer
(5)
previous value =40
new value =60
so, change = new value - previous value
change =60-40
change =20
percent of change = ((change)/(previous value))*100
percent of change is
[tex]=\frac{20}{40}\times 100[/tex]
[tex]=50[/tex]
percent of change is 50%..................Answer
Answer:
1. b) 10%
2. d) 12%
3. a) 20%
4. d) 8%
5. d) 50%
Step-by-step explanation:
We will use percentage change formula to solve our given problems.
[tex]\text{Percent change}=\frac{\text{Final value - Initial value}}{\text{initial value}}*100[/tex]
1. The percent of change when the price of a radio changes from $40.00 to $44.00.
[tex]\text{Percent change}=\frac{44-40}{40}*100[/tex]
[tex]\text{Percent change}=\frac{4}{40}*100[/tex]
[tex]\text{Percent change}=\frac{1}{10}*100[/tex]
[tex]\text{Percent change}=1*10=10[/tex]
Therefore, the price of radio increased by 10% and option b is the correct choice.
2. The percent of change when the price of an oven changes from $450 to $396.
[tex]\text{Percent change}=\frac{396-450}{450}*100[/tex]
[tex]\text{Percent change}=\frac{-54}{450}*100[/tex]
[tex]\text{Percent change}=-0.12*100[/tex]
[tex]\text{Percent change}=-12[/tex]
Therefore, the price of oven decreased by 12% and option d is the correct choice.
3. The top player’s scoring average changes from 20 points per game to 24 points per game.
[tex]\text{Percent change}=\frac{24-20}{20}*100[/tex]
[tex]\text{Percent change}=\frac{4}{20}*100[/tex]
[tex]\text{Percent change}=4*5[/tex]
[tex]\text{Percent change}=20[/tex]
Therefore, the player's scoring average increased by 20% and option a is the correct choice.
4. At the start of the football season, Jorge weighed 150 pounds. At the end of the season, he weighed 138 pounds.
[\text{Percent change}=\frac{138-150}{150}*100[/tex]
[tex]\text{Percent change}=\frac{-12}{150}*100[/tex]
[tex]\text{Percent change}=-0.08*100[/tex]
[tex]\text{Percent change}=-8[/tex]
Therefore, the Jorge's weight decreased by 8% and option d is the correct choice.
5. Sara raised her raw score on a math test from 40 to 60.
[tex]\text{Percent change}=\frac{60-40}{40}*100[/tex]
[tex]\text{Percent change}=\frac{20}{40}*100[/tex]
[tex]\text{Percent change}=20*2.5[/tex]
[tex]\text{Percent change}=50[/tex]
Therefore, Sara's score on math test increased by 50% and option d is the correct choice.
