Respuesta :
Given:
Concentration of phenol = 0.31 M
Ka (acid dissociation constant) = 1.3 * 10⁻¹⁰
To determine:
The pH of the solution
Explanation:
C6H5OH ↔ C6H5O⁻ + H⁺
Initial 0.31 M 0 0
change -x +x +x
Equlib 0.31-x x x
Ka = [C6H5O⁻][H⁺]/[C5H5OH]
1.31*10⁻¹⁰ = x²/0.31-x
x =[H+]= 6.37*10⁻⁶M
pH = -log[H+] = -log(6.37*10⁻⁶) = 5.19
Ans: pH of the solution is 5.19
