The perimeter of the triangle ABC is [tex]10 \ + \ \sqrt{10} \ units[/tex].
The given parameters:
- Triangle ABC = Isosceles triangle
The length of AC = 3-(-2) = 5 unit
The length of AC = length of BC = 5 unit
The length of BC is calculated by applying Pythagoras theorem as follows;
[tex]BC^2 = (4-1)^2 + (3-2)^2\\\\BC^2 = 3^2 + 1^2\\\\BC^2 = 10\\\\BC = \sqrt{10} \\\\[/tex]
The perimeter of the triangle ABC is calculated as follows;
[tex]P = AB + AC + BC\\\\P = 5 \ + \ 5 \ + \ \sqrt{10} \\\\P = 10 \ + \ \sqrt{10} \ \ units[/tex]
Learn more about perimeter of triangle here: https://brainly.com/question/24382052
