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A restaurant serves an appetizer special and a dessert special each night. Each appetizer is the same price. Each dessert is the same price. The price of the appetizer special is On Tuesday, the restaurant collected $450 selling 42 appetizers and 19 desserts. • On Friday, the restaurant collected $432 selling 27 appetizers and 36 desserts. What is the cost of each special? different from the price of the dessert special.

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Answer:

Appetizer cost = $8/-

Dessert cost = $6/-

Step-by-step explanation:

Given that,

42x + 19 y= 450

27x +36 y = 432

Solving above equations, we get:

x= 8

y= 6

Therefore,

Appetizer cost = $8/-

Dessert cost = $6/-

Answer: The cost of appetizer is $8 and the cost of dessert is $6.

Step-by-step explanation:

Let cost of appetizer be 'x'.

Let cost of desserts be 'y'.

According to question,

On Tuesday, it becomes,

[tex]42x+19y=$450[/tex]

On Friday, it becomes,

[tex]27x+36y=\$432[/tex]

By graphing method, we get that,

x= 8 and y = 6

Hence, the cost of appetizer is $8 and the cost of dessert is $6.

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