Answer:
[tex]57\°[/tex]
Step-by-step explanation:
we know that
The sum of the measures of the exterior angles of a polygon is always [tex]360\°[/tex]
so
in this problem
[tex](14x+6)\°+(6x-3)\°+(4x+8)\°+(49\°)+(3x+30)\°=360\°[/tex]
solve for x
[tex](27x+90)\°=360\°[/tex]
[tex]27x=360\°-90\°[/tex]
[tex]27x=270\°[/tex]
[tex]x=10\°[/tex]
Find the measure of exterior angle A
[tex](6x-3)\°=(6*10-3)\°=57\°[/tex]
