thomasshy116
contestada

I need help! Can someone please answer this question?
What are the restrictions of q²+3q-4 over q²-7q-8, and why?

A. q≠ -1 and q≠ 8
B. q≠ -1 and q≠4
C. q≠ 1 and q≠-8

Respuesta :

gmany

[tex]\dfrac{q^2+3q-4}{q^2-7q-8}\\\\\text{The restrictions of experssion}\\\\q^2-7q-8\neq0\\\\q^2+q-8q-8\neq0\\\\q(q+1)-8(q+1)\neq0\\\\(q+1)(q-8)\neq0\iff q+1\neq0\ \wedge\ q-8\neq0\\\\Answer:\ \boxed{A.\ q\neq-1\ and\ q\neq8}[/tex]

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