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Sodium Oxide (Na2O) can react with hydrochloric acid (HCl) to produce sodium chloride (NaCl) and water (H2O) according to the following equation: Na2O + 2HCl -> 2NaCl + H2O How many total atoms are present before and after the reaction

Respuesta :

Answer:

Na2O + 2HCl -> 2NaCl + H2O then it wil be 10.3 atoms left in the cycle


Step-by-step explanation: you would take

(Na2O) then (HCl) then (NaCl) and, (H2O)

And you would got to the table of atoms and put them together if you look at the name of a chemical it show a number well you would divide them in to fractions and the denominator you would need to focus on because that is going to be your answer.  

Answer:

7 before and 7 after

Step-by-step explanation:

Before:

Na2O=3 atoms

2HCl=4 atoms

After:

2NaCl=4 atoms

H2O=3 atoms

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