Drag and drop the correct answer into each box to complete the proof.


parallelogram K L M N where K N is parallel to L M and K L is parallel to M N


Given: Parallelogram KLMN


Prove: ∠N≅∠L and ∠M≅∠K


Statement Reason

Parallelogram KLMN Given

KL¯¯¯¯¯∥NM¯¯¯¯¯¯¯ and KN¯¯¯¯¯¯∥LM¯¯¯¯¯¯

m∠K+m∠N=180°


m∠L+m∠M=180°


m∠K+m∠L=180°


Same-Side Interior Angles Theorem

m∠K+m∠N=m∠K+m∠L


m∠L+m∠M=m∠K+m∠L


m∠N=m∠L


m∠M=m∠K


∠N≅∠L and ∠M≅∠K Angle Congruence Postulate

Drag and drop the correct answer into each box to complete the proofparallelogram K L M N where K N is parallel to L M and K L is parallel to M NGiven Parallelo class=
Drag and drop the correct answer into each box to complete the proofparallelogram K L M N where K N is parallel to L M and K L is parallel to M NGiven Parallelo class=

Respuesta :

Answer:  Statements reasons are,

In First blank - By the property of parallelogram

In second blank - transitive property of equality

In third blank - Subtraction property of equality

Step-by-step explanation:

Transitive property of equality states that if a = b and b=c then a =c

While, Subtraction property of equality states that  subtraction of a number from the each side of equation does not change the equality of the equation.

That is, If a = b then we can write, a- c = b-c

Here, Given: Parallelogram KLMN

And, the opposite sides of the parallelogram are congruent and equal.

Prove: ∠N≅∠L and ∠M≅∠K

            Statement                                        Reason

1. KL∥NM and KN∥LM                     1. By the property of parallelogram

2. m∠K+m∠N=180°                            2. Same-Side Interior Angles Theorem



m∠L+m∠M=180°



m∠K+m∠L=180°

3.m∠K+m∠N=m∠K+m∠L                3. Transitive property of equality

m∠L+m∠M=m∠K+m∠L

4.m∠N=m∠L                                     4. By subtraction property of

m∠M=m∠K                                         equality  

5.  ∠N≅∠L and ∠M≅∠K                  5. Angle Congruence Postulate  



Answer:

Step-by-step explanation:

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