Answer:
Option 3 - The distance Ship A traveled in 1 h is less than the distance Ship B traveled in 1 h.
Step-by-step explanation:
Given : Two cruise ships left port at the same time. The distance Ship A traveled is modeled by the function d(t)=47t where d represents distance in miles and t represents time in hours. Ship B traveled a total of 165 miles in 3 hours.
To find : How does the distance Ship A traveled in 1 hour compare to the distance Ship B traveled in 1 hour?
Solution :
Ship B traveled a total of 165 miles in 3 hours.
In 3 hour ship traveled 165 miles
In 1 hour ship traveled [tex]\frac{165}{3}=55[/tex] miles.
Distance traveled by Ship B in 1 hour is 55 miles.
The distance Ship A traveled is modeled by the function [tex]d(t)=47t[/tex] where d represents distance in miles and t represents time in hours.
Distance traveled in 1 hour is put t=1,
[tex]d(t)=47(1)=47[/tex]
Distance traveled by Ship A in 1 hour is 47 miles.
So, The distance Ship A traveled in 1 h is less than the distance Ship B traveled in 1 h.
Therefore, Option 3 is correct.
