Answer:
[tex]y=6x+22[/tex]
Step-by-step explanation:
We do not have enough information for slope intercept form. But we can use the point-slope formula to find the information. The formula is [tex]y -y_{1} =m(x -x_{1})[/tex] where we substitute a point (x,y) for [tex](x_{1},y_{1})[/tex].
We know it is parrallel to the listed line in slope intercept form. Recall, y=mx+b tells that the m is slope. Since y=6x-1, then m=6. We also have a point for the new line (-3, 4). We input m and [tex]x_{1} =-3\\y_{1}=4[/tex].
[tex]y-4=6 (x-(-3))\\y-4=6 (x+3)[/tex]
We now simplify the parenthesis and solve for y.
[tex]y-4=6x+6(3)\\y-4=6x+18[/tex]
We add 4 to both sides to isolate y,
[tex]y-4+4=6x+18+4\\y=6x+22[/tex]
This is slope intercept form. The line as slope 6 and y-intercept (0,22) or b=22.