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What is the equation of the line (in point-slope form) that is parallel to y−5= − 1 /3 (x+2) and passes through the point (6,−1)?

Respuesta :

frika

Answer:

[tex]y-(-1)=-\dfrac{1}{3}(x-6)[/tex]

Step-by-step explanation:

Parallel lines have the same slope. The slope of the given line is [tex]-\dfrac{1}{3},[/tex] then the equation of the parallel line that passes through the point (6,-1) in point-slope form is

[tex]y-(-1)=-\dfrac{1}{3}(x-6).[/tex]

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