Answer:
[tex]300(1.15)^6[/tex]
Step-by-step explanation:
Given,
The fish population is increasing per year,
That is, the population is increasing exponentially,
Since, the population that is increasing exponentially is,
[tex]A=P(1+r)^{t}[/tex]
Where, P is initial population,
r is rate of increasing per period,
t is number of periods,
Here, P = 300,
r = 15 % = 0.15,
t = 6 years,
Hence, the population of fish after 6 years would be,
[tex]A=300(1+0.15)^6[/tex]
[tex]=300(1.15)^6[/tex]
Which is the required equation.
300 × (1 + 15%) ⁶ is the equation that will show the number of fish in the pond after 6 years.
To find the number of fish in the pond after a certain number of years, use the future value formula:
Future value = Amount × ( 1 + rate) ^ number of years
Number of fish after 6 years = Number of fish now × (1 + 15%) ⁶
= 300 × (1 + 15%) ⁶
In conclusion, if you want to find out the number of fish in the pond after 6 years, use this formula: 300 × (1 + 15%) ⁶
Find out more at https://brainly.com/question/11730399
