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A 0.145kg baseball traveling at 35 m/s is hit by Barry Bonds’ bat so that it rebounds in the opposite direction at 40 m/s. Determine the ball’s change in momentum (magnitude and direction)

Respuesta :

Answer:

-10.88 kg m/s

Explanation:

The change in momentum of the ball is given by:

[tex]\Delta p= m\Delta v=m(v-u)[/tex]

where

m is the mass of the ball

u is the initial velocity of the ball

v is the final velocity of the ball

Let's take the initial direction of the ball as positive direction. In this reference frame, we have:

m = 0.145 kg

u = +35 m/s

v = -40 m/s

Therefore, the change in momentum is

[tex]\Delta p=(0.145 kg)((-40 m/s)-(+35 m/s))=-10.88 kg m/s[/tex]

And the sign is negative since the change in momentum is in the opposite direction to the initial direction of the ball.