Answer:
The boy's acceleration toward the girl is 2.08 m/s^2.
Explanation:
According the Newton's Third Law, the force causing the girl accelerate towards the boy will be me with equal counter-force causing the boy to accelerate towards the girl. These forces will be of equal magnitude and allows us to determine the boy's acceleration:
[tex]F_{boy} = F_{girl}\\F_{girl} = m_{girl}\cdot a_{girl} = 37kg\cdot 3.2 \frac{m}{s^2}=118.40N\\\implies F_{boy} = 118.40N\\a_{boy} = \frac{F_{boy}}{m_{boy}}=\frac{118.4N}{57kg}=2.08\frac{m}{s^2}[/tex]
The boy's acceleration toward the girl is 2.08 m/s^2.
