Answer: 1/36
Explanation:
For Misty to get the roll, he wants each dice to have 4.
event A: to get 4 one first dice
event B: To get 4 on second dice
Probability to get 4 on a dice
[tex]P(A)=P(B)= \frac {1}{4}[/tex]
The two events are simultaneous and independent:
The probability that both the dice would have 4 is
[tex]P(A) \times P(B) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}[/tex]
Hence, there is 1/36 probability for Misty to get the roll he wants.
