Answer:
Part 1) [tex]8.3\ years[/tex]
Part 2) [tex]\$2,424.27[/tex]
Part 3) [tex]\$2,266.02[/tex]
Part 4) In the procedure
Step-by-step explanation:
Part 1) we know that
The compound interest formula is equal to
[tex]A=P(1+i)^{n}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
i is the interest rate in decimal
n is number of years
n is the number of times interest is compounded per year
in this problem we have
[tex]P=\$2,200\\ A=\$2,500\\ r=0.0155\\n=?[/tex]
substitute in the formula above
[tex]\$2,500=\$2,200(1+0.0155)^{n}[/tex]
[tex](2,500/2,200)=(1.0155)^{n}[/tex]
Applying log both sides
[tex]log(2,500/2,200)=(n)log(1.0155)[/tex]
[tex]n=log(2,500/2,200)/log(1.0155)[/tex]
[tex]n=8.3\ years[/tex]
Part 2)
in this problem we have
[tex]P=?\\ A=\$2,500\\ r=0.0155\\n=2\ years[/tex]
substitute in the formula above
[tex]\$2,500=P(1+0.0155)^{2}[/tex]
[tex]\$2,500=P(1.0155)^{2}[/tex]
[tex]P=\$2,500/(1.0155)^{2}[/tex]
[tex]P=\$2,424.27[/tex]
Part 3) in this problem we have
[tex]P=\$2,000\\ r=0.018\\n=7\ years[/tex]
substitute in the formula above
[tex]P=\$2,000(1+0.018)^{7}=\$2,266.02[/tex]
The money is not enough
Part 4)
I would personally increase the investment from 2,200 dollars so that it grows to 2,500 dollars at the time I want to make the trip, for example if I wanted to make the trip in two years, I would increase the initial investment from 2200 dollars to 2427 dollars.