Answer:
16.68 L
Explanation:
First of all, we need to calculate the number of moles corresponding to 25.2 g of CO2.
The molar mass of CO2 is 44.01 g/mol, therefore the number of moles is:
[tex]n=\frac{m}{M_m}=\frac{25.2 g}{44.01 g/mol}=0.573 mol[/tex]
So now we can use the ideal gas equation:
[tex]pV=nRT[/tex]
where:
p = 0.84 atm is the gas pressure
V = ? is the volume
n = 0.573 mol is the number of moles
R = 0.08206 L atm / K mol is the gas constant
T = 25°c = 298 K is the gas temperature
Substituting into the equation and re-arranging it, we find the volume:
[tex]V=\frac{nRT}{p}=\frac{(0.573 mol)(0.08206 Latm/Kmol)(298 K)}{0.84 atm}=16.68 L[/tex]
