Answer : The volume at STP will be 0.2944 L
Solution : Given,
Initial volume = 500 ml
Initial temperature = [tex]60^oC=273+60=333K[/tex] [tex](0^oC=273K)[/tex]
Initial pressure = 500 mmHg = [tex]\frac{500}{760}=.658atm[/tex] [tex](1atm=760mmHg)[/tex]
At STP,
Temperature = 298 K
Pressure = 1 atm
Formula used : [tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure
[tex]P_2[/tex] = pressure at STP
[tex]T_1[/tex] = initial temperature
[tex]T_2[/tex] = temperature at STP
[tex]V_1[/tex] = initial volume
[tex]V_2[/tex] = volume at STP
Now put all the given values in this formula, we get
[tex]\frac{(0.658atm)\times (500ml)}{333K}=\frac{(1atm)\times V_2}{298K}[/tex]
By rearranging the terms, we get the volume at STP
[tex]V_2=294.42ml=0.2944L[/tex] (1 L = 1000 ml)
Therefore, the volume at STP will be 0.2944 L
Using the formula for the gas laws, the new volume of the gas is 270 ml.
The acronym STP stands for standard temperature and pressure. We have the following information
P1 = 500 mm Hg
T1 = 60 + 273 = 333 K
P2 = 760 mmHg(SP)
T2 = 273 K (ST)
V1 = 500 ml
V2 = ?
Using the formula;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = P1V1T2/P2T1
V2 = 500 mm Hg * 500 ml * 273 K/760 mmHg * 333 K
V2= 68250000/253080
V2= 270 ml
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