equations
solution
Let "a" and "c" represent the numbers of adult and children's tickets sold, respectively. The problem statement tells us two relationships between these values:
... 20a +10c = 15000 . . . . . . total revenue from ticket sales
... c = 3a . . . . . . . . . . . . . . . . relationship between numbers of tickets sold
Using the expression for c, we can substitute into the first equation to get ...
... 20a +10(3a) = 15000
... 50a = 15000
... a = 15000/50 = 300 . . . . . adult tickets sold
... c = 3·300 = 900 . . . . . children's tickets sold