Answer: The four [tex]sp^3[/tex] hybridized orbitals on Sb makes up the sigma bonds between Sb and F in antimony(iii) fluoride ,[tex]SbF_3[/tex]
Explanation:
According to VESPR theory:
Number of electrons around the central atom : [tex]\frac{1}{2}[V+N-C+A][/tex]
V = number of valence electrons
N = number of neighboring atoms
C = charge on cation
A = charge on an anion
In antimony(III) fluoride ,
Antimony being central atom: V= 5,N =3,C=0,A=0
Number of electrons : [tex]\frac{1}{2}[V+N-C+A]=4[/tex]
Number of electrons around the central atom are 4 which means that [tex]SbF_3[/tex] molecule has four [tex]sp^3[/tex] hybridized orbitals.
