Answer:
4.29 millimeters
Explanation:
Bats emit ultrasound waves: in air, ultrasound waves travel at a speed of
[tex]v=343 m/s[/tex]
The frequency of the waves emitted by this bat is:
[tex]f=80.0 kHz = 80,000 Hz[/tex]
Therefore we can find the wavelength of the wave emitted by the bat by using the relationship between speed, frequency and wavelength:
[tex]\lambda=\frac{v}{f}=\frac{343 m/s}{80,000 Hz}=4.29\cdot 10^{-3} m=4.29 mm[/tex]
