Answer:
see explanation
Step-by-step explanation:
given a quadratic in standard form : y = ax² + bx + c : a ≠ 0
Consider the coefficient of the x² term
• If a > 0 then vertex is a minimum and graph opens up
• If a < 0 then vertex is a maximum and graph opens down
f(x) = x² - 5x - 7 is in standard form
with a = 1, b = - 5 and c = - 7
Since a > 0 then vertex is a minimum and graph opens up
The graph of the function, f(x) = x2 - 5x - 7 opens up and has minimum at (2.5,-13.2).
f(x) = x2 - 5x - 7 is given. Where the graph opens and has min or max to be determine.
Functions is the link between set of values domain and range.
Here, f(x) = x2 - 5x - 7
a = 1, meanwhile graph has minimum and opens up.
Minimum of f(x) = d/dx (x2 - 5x - 7) >0
2x-5>0
x >5/2
x > 2.5
Now at x = 2.5,
y = 2.5^2-2.5*5-7
y = -13.2
Thus, the graph of the function, f(x) = x2 - 5x - 7 opens up and has minimum at (2.5,-13.2).
learn more about function here:
brainly.com/question/21145944
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